Edward C. answered 04/21/16
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Caltech Grad for math tutoring: Algebra through Calculus
Take the derivative of the function before you plug in any values for x
f'(x) = (2^x)*ln2
So f'(0) = (2^0)*ln2 = ln2
f'(1) = (2^1)*ln2 = 2*ln2
...
etc.