
Ron G. answered 04/16/16
Tutor
4.4
(26)
Multiple levels Math, Science, Writing
OK. You'll have to integrate the growth rate with respect to time, without forgetting the amount of area covered at the start.
A = 2010 + ∫ 8t1/2 dt (as t goes from 0 to 24)
A = 2010 + [(16/3) t3/2] (as t goes from 0 to 24)
A = 2010 + 627 = 2637 acres
You don't integrate the 2010 here because whatever effects of the passing of time have already taken place over that area. You just treat it as a constant and add it to the result of integration.
Cheers!