Algbrea 2 Math

Question

(k^1/4)^-6/over (k9)^1/2=  

 

Use positive exponents only

Answer 1

minor correction to Michael's answer:

 

(k^1/4)^-6/ (k⁹)^1/2=1/((k^1/4)⁶(k⁹)^1/2)=1/k^6/4+^9/2=1/k^24/4=1/k⁶

Answer 2

(k^1/4)^-6/ (k⁹)^1/2=1/((k^1/4)⁶(k⁹)^1/2)=1/k^6/4+9/2=1/k^24/4=1/k⁶

Thank you very much Fayvor!