A fair die is rolled and a fair coin is tossed. The random variable X is defined as the number obtained on the die minus the number of heads (0 or 1) resulting

Question

I tried this problem and my numbers weren't adding up. No need to make a table just the probability of each value is good enough.

Answer 1

Outcomes...

Die   H   X

1      0   1

1      1   0

2      0   2

2      1   1

3      0   3

3      1   2

4      0   4

4      1   3

5     0    5

5     1    4

6     0    6

6     1    5

 

each of the above 12 outcomes is equally probable.

 

P(X=0) = 1/12, P(X=1) = 2/12 = 1/6, ...

P(X=5) = 2/12 = 1/6,

P(X=6) = 1/12