Roman C. answered 04/05/16
Tutor
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Masters of Education Graduate with Mathematics Expertise
The sample space for rolling a die together with flipping a coin consists of ordered pairs (1...6 , H or T). There are 12 such pairs and they are equally likely.
The possible outcomes for X are
0: (1,H)
1: (1,T) or (2,H)
2: (2,T) or (3,H)
3: (3,T) or (4,H)
4: (4,T) or (5,H)
5: (5,T) or (6,H)
6: (6,T)
So the probability table is
x | P(X = x)
-----------------
0 | 1/12
1 | 1/6
2 | 1/6
3 | 1/6
4 | 1/6
5 | 1/6
6 | 1/12