Andrew M. answered 03/30/16
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
I know it's hard to picture this in your head...
But you end up with 6 equilateral triangles
of side length 6 spaced around the nonshaded
hexagon in the center.
Take 1 triangle with side lengths of 6.
Draw a vertical line from the point at the
top to the center of the base, cutting the
triangle in half.
This divides the single triangle into two
right triangles. Each has
a base of 3 making one leg, an angled side of length 6
representing the hypotenuse, and the other leg of
unknown length which will represent the height
of the original triangle.
|\
x | \ 6
|__\
3
This is one half of one of the 6 triangles.
From the Pythagorean theorem..
a2+b2 = c2 where a,b are the legs,
and c is the hypotenuse of a right
triangle we can find x.
x2 + 32 = 62
x2 + 9 = 36
x2 = 36-9
x2 = 27
x = √27
x = √[(9)(3)]
x = √[(32)(3)]
x = 3√3
This is the height of the triangle.
Now we can find the area of one of the 6 triangles.
Area = (1/2)(base)(height)
Area = (1/2)(6)(3√3)
Area = 3(3√3)
Area = 9√3
This is the area of 1 of your 6 shaded triangles.
Since we have 6, multiply this by 6 for final total.
Area total shaded = 6(9√3) = 54√3