Sami, I hope I can still help!
We know that distance = rate x time. Since the distance there and back are the same, we set the two products equal to each other.
If s = the speed of the plane, we add the windspeed coming back (s + 15) and subtract it going out (s - 15).
Sooo, we have...
5(s - 15) = 3(s + 15)
I bet you can solve for s from here!