a butcher has some 60% lean hamburger and some 85% lean hamburger how much of each should be used to make 200 pounds of 80%

Question

a butcher has some 60% lean hamburger and some 85% lean hamburger how much of each should be used to make 200 pounds of 80% Lean hamburger

Answer 1

the formula to solve this question is C1W1 +C2W2 = C3W3 where C = Concentration, and W = Weight

 

let x = Weight of 85% hamburger, then 200p - x = Weight of 60% hamburger

 

to simplify the calculation, let's convert the % figures to decimals, so 60% = 0.6, 80% = 0.8, and 85% = 0.85

 

Our equation becomes 0.85x + 0.6(200 - x) = 200•0.8

 

expanding, we get 0.85x + 120 - 0.6x = 160

which becomes 0.25x = 40, and x = 160 pounds

so, 160 pounds at 85%, and 40 pounds at 60%

 

Proof: 0.85 x 160p + 0.6 x 40p = 0.8 x 200p

136p + 24p = 160p