Four friends sit at a square table for lunch each day. If theit positiond are random, what is the probability Luis sits across from Pam two days in a row

Question

It's probabilityof compound events

Answer 1

There are 24 possible arrangements of the four friends (4*3*2*1).  Of those there are 8 that have Luis across from Pam (4 *2) So the probability on any given day is 1/3. To do it two days in a row would be 1/3*1/3 or 1/9