Mark M. answered 03/20/16
Tutor
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
f(x) ≈ L(x) = f(x0) + f'(x0)(x - x0)
Let f(x) = (x+1)1/3, x0 = 0, x = 0.2
(1.2)1/3 = f(0.2) ≈ f(0) + f'(0)(0.2 - 0)
= (1)1/3 + (1/3)(1)-2/3(0.2)
= 1 + 1/15
= 16/15