Melanie Z.

asked • 03/18/16# (sinx+cosxcotx)/(cosxcscx)=secx

## 3 Answers By Expert Tutors

Yohan C. answered • 03/18/16

Math Tutor (up to Calculus) (not Statistics and Finite)

^{2}x cos x

^{2}x cos

^{2}x

^{2}x + cos

^{2}x 1

**cot x**=

**cos x csc x**

**cot x**= sec x

**cot x = cos x / sin x**

**(sin x)**cos x

**cos x**1

^{2}x cos

^{2}x 1

Arthur D. answered • 03/18/16

Mathematics Tutor With a Master's Degree In Mathematics

Melanie Z.

03/19/16

Arthur D.

03/19/16

Alan G. answered • 03/18/16

Successful at helping students improve in math!

^{2}x + cos

^{2}x)/sin x · sin x/ cos x

Arthur D.

03/19/16

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Alan G.

03/18/16