Alan G. answered 03/18/16
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|u| = 5 and |v| = √42, while u·v = 12 + 0 + 20 = 32.
So,
cos θ = 32/(5√42), and
θ = cos-1 (32/(5√42)) ≈ 0.1580 rad.
Next, projv u =(u·v)/(v·v) v = 32/42 (-4i + j + 5k) = 16/21 (-4i + j + 5k) = -64/21 i + 16/21 j + 80/21 k .
I assume scalv u is the scalar projection of u onto v, which is |u| cos θ = 5 · 32/(5√42) = 32/√42 . This happens to be the magnitude of projv u, since it points in the same general direction as v (u·v is positive).
If my assumption was wrong, you may need to correct my answer to the last question.