Arthur D. answered 03/13/16
Tutor
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Mathematics Tutor With a Master's Degree In Mathematics
7∏/12=7*180/12=7*15=105º
5sin(105º)=5sin(210/2)
sin(210/2)=±√(1-cos210)/2
±√(1-[-√3/2])/2
±√(1+√3/2)/2
±√[(2+√3)/2]/2
±√[(2+√3)/4]
±√(2+√3)/2 (the second 2 is not inside the √ symbol)
now multiply by 5
(5/2)√(2+√3)
9cos(105º)=9cos(210/2)
cos(210/2)=±√(1+cos210)/2
±√(1-√3/2)/2
±√[(2-√3)/2]/2
±√[2-√3]/4
±√(2-√3)/2 (the second 2 is not inside the √ symbol)
now multiply by 9
-(9/2)√(2-√3)
5tan(210/2)=±5√[(2+√3)/2]/[(2-√3)/2]=
±5√[(2+√3)/(2-√3)]
rationalize the denominator
±5√(1/[7-4√3]
-5/√(7-4√3)
Arthur D.
tutor
Thank you, Mark. I'll make my corrections. Feel free to correct me again if I make a mistake correcting these.
Arthur D.
Report
03/14/16
Mark M.
03/13/16