Roman C. answered • 03/12/16
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m1 = 100 kg, m2 = 200 kg
r12 = (22 + 62)m2 = 40 m2, r22 = (32 + 72)m2 = 58 m2
I = m1r12 + m2r22 = (100 kg)(40 m2) + (200 kg)(58 m2) = 15600 kg·m2
Vedant D.
asked • 03/12/16Find the moment of inertia of the system
the position vectors of two point like object of mass 100kg and 200kg are (2,4,6)m and (3,5,7)m respectively.Find the moment of inertia of the system about Y- axis
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