Raymond B. answered 14d
Tutor
5
(2)
Math, microeconomics or criminal justice
(x+2)(x-3)/(x-3)(x+1)(x-2)=(x+2)(x-3)/(x-3)(x^2-x-2)=
(x+2)(x-3)/(x^3-4x^2+x+6)
= (x^2 -x-6)/(x^3-4x^2+x+6)
Gerami S.
asked 03/09/16Raymond B. answered 14d
Math, microeconomics or criminal justice
(x+2)(x-3)/(x-3)(x+1)(x-2)=(x+2)(x-3)/(x-3)(x^2-x-2)=
(x+2)(x-3)/(x^3-4x^2+x+6)
= (x^2 -x-6)/(x^3-4x^2+x+6)
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