the perimeter of a rectangle is 32 inches. what is the width of the rectangle if the length is 4 more than twice the width?

Question

The perimeter of a rectangle is 32 inches. What is the width of the rectangle if the length is 4 more than twice the width?

Answer 1

Hello Bob.

 

From the first sentence

P = 32" = 2L + 2W

 

From the 2nd sentence

L = 2W + 4

 

Substitute the expression for L in the first equation.

 

32 = 2(2W+4) + 2W

32 = 4W + 8 + 2W

32 = 6W + 8

24 = 6W

4 = W

 

The width is 4"