David W. answered 03/06/16
Tutor
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Experienced Prof
If there is a "first" marble and there is a "second" marble (note: there is only 1 yellow).
The combinations are:
first second
---- --------
Y B
Y P
B Y
B B
B P
P Y
P B
P P
There are 8 combinations.
Now, if there is not a "first" marble and a "second" marble, how many combinations are there? (that is, position doesn't matter: Y-B is the same as B-Y) ??