Calc. question and I need help please!

Question

If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1) = −3, g '(3) = 2, then find h '(1) if h(x) = the quotient of f of x and g of x..

Answer 1

h(x) = f(x)/g(x)

 

By the quotient rule, h'(x) = [f'(x)g(x) - f(x)g'(x)]/(g(x))²

 

Now, plug in x = 1 and then substitute the given relevant values.