Find the length and width of the rectangle.

Question

The perimeter of a rectangle is 36 meters. The length of the rectangle is 4 meters longer than the width. 

Answer 1

Let x = width

 

Let y = length

 

2x + 2y = 36

 

y = x + 4

 

Using the substitution method, rewrite the first equation as 2x +2(x + 4) = 36

 

2x +2x + 8 = 36

 

4x = 28

 

x = 7

 

y = 7+4 = 11

 

The width is 7 meters, and the length is 11 meters.

 

Checking 2(7) + 2(11) = 36.

Answer 2

Hi Simrat,

 

The perimeter of a rectangle is 36 meters. The length of the rectangle is 4 meters longer than the width.

 

 

A rectangle has four sides with opposite sides equal.

To find the perimeter, add up the measure of all four sides.

 

Let w=width

let w+4=the length

 

 

w+w+w+4+w+4=36

4w+8=36

4w=28

w=7

 

To find the length use w+4=7+4=11

 

ANSWER:  The width is 7 meters and the length is 11 meters.

 

We're finished