John R.

# infinite limits and e^x

I understand that as x approaches (+) infinity, e^x = infinity.

I also understand that as x approaches (-) infinity, e^x = 0.  The graph makes sense.

So, as x approaches (-) infinity, -e^x = infinity...  Is this true?

By: Tutor
4.7 (16)

Physics graduate tutoring in math and sciences. Daniel O.

You could add that, as x approaches -infinity, e^x approaches 0+ (zero from the positive side of the y-axis) and -e^x approaches 0- (zero from the negative side of the y-axis).

More simply, ie from a graph, as x approaches negative infinity, e^x approaches zero from above, and -e^x approaches zero from below.

Report

11/19/12

John R.

OK...  thanks!   That's what I suspected.  I think my solutions guide is wrong...

Report

11/19/12 Daniel O.

What does your solutions guide say? e^(-x) would approach infinity as x approaches negative infinity.

Report

11/19/12

## Still looking for help? Get the right answer, fast.

Get a free answer to a quick problem.
Most questions answered within 4 hours.

#### OR

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.