Solve P= an+(n-1)d^2 for n

Question

d is squared

solving for n

Answer 1

Hi Joel, to solve this problem for n, it is necessary to isolate the n.

 

P = an + (n - 1) * d²

 

Distribute the d² to clear the parenthesis:

 

P = an + nd² - d²

 

Add d² to both sides:

 

P + d² = an - nd²

 

Remove the n from both terms on the right side:

 

P + d² = n * (a - d²)

 

Divide both sides by a - d²:

 

(P + d²) / (a - d²) = n

 

Final answer: 

 

n = (P + d²) / (a - d²)

 

Questions?