a chemist has two solutions 1 20% acid and the other 60% acid how much of each solution to make 120 milliliters that is 28% acid

Question

I need help with this math problem :-)

Answer 1

.2x + .6(120-x) = .28(120)

-.4x = .28(120) -.6(120

.4x = .32(120)

x = .32(120)/.4 = 96 mL of 20%

24 mL of 60%

to yield a mixture of 120 mL of 28%

60-28 =32

28-20 = 8

32/8 =4

96/24 = 4