Youngkwon C. answered 02/24/16
Tutor
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Knowledgeable and patient tutor with a Ph.D. in Electrical Eng.
Hi Cierra,
Remembering that sin(·) and cos(·) are positive and negative,
respectively, in the second quadrant,
from either the Pythagorean theorem or
the formula sin2θ + cos2θ = 1,
we can find out the value of cos(u) and sin(v).
sin(u) = 4/5, cos(u) = -3/5 ⇒ tan(u) = -4/3
sin(v) = 24/25, cos(v) = -7/25 ⇒ tan(v) = -24/7
Plugging in the above values into the trigonometric identy
tan(u-v) = [tan(u) - tan(v)]/[1 + tan(u)·tan(v)]
= [(-4/3) - (-24/7)]/[1 + (-4/3)·(-24/7)]
= (-4/3 +24/7)/[1 + (4/3)·(24/7)]
= (44/21)/[1 + (96/21)]
= 44/117
Hope this helps.