Perpendicular to the line 3x-4y=-8

Question

 Im writing and equation in slope-intercept form for the line with given condition that contains the point (-6,5)

Answer 1

The answer:

 for line 1 :-

y = mx+b

-4y+3x=8       dividing both sides by -4

y = (3/4) *x - 2

m1 = 3/4

for line 2:-

 m2 = -1/m1 = - 4/3

slope intercept form

m2 = (y-y1)/(x-x1)

-4/3 = (y - 5) / ( x+6)