From the problem statement, we are given the slope "m=-6" and a point (7,9) on the line. We will use the "point-slope" form to write the equation of that line...
(y-y1)=m(x-x1)....."point-slope" form
(y-9)=(-6)(x-7)......substitute values for "m, x1, y1"
y-9=-6x+42.......distribute (-6), RHS
∴ y=-6x+51.......add 9, both sides
So our equation in "point-slope" form is "y=-6x+51".
Let's check our work. Substitute the point (7,9) back into our equation...
y=-6x+51........derived equation
9=(-6)(7)+51...substitute for "x, y"
9=-42+51.......simplify
9=9.................true, √check, our equation is
correct
Always check your solution and work!