How to find vertex, focus, directix and axis of symmetry of a parabola.

Question

Find the vertex, focus, directrix, and axis of symmetry of the parabola.
(y=1)^2=-2(x-3)

Answer 1

(y-1)^2 = -2(x-3)

is a horizontal leftward opening parabola with vertex (3,1)

axis of symmetry is y=1

directrix & focus are equidistant from the vertex

focus has same y coordinate as the vertex, 1

directr