Evaluate the geometric series below?

Question

Evaluate the geometric series below.

 

∑_(i=0)^∞  12(4/7)^i

Answer 1

Daniel,

 

A geometric series is of the form ∑(i=0)^∞ arⁱ

It's a geometric series when |r|<1

 

∑(i=0)^∞ 12(4/7)^i

 

In this case

a = 12

r = 4/7

 

The series converges at

a/(1-r) = 12/(1-4/7) = 12/(3/7) = 28