Marlene S. answered 01/31/16
Tutor
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Retired Actuary with 20+ years of Calculus Tutoring Experience
Hi Emil.
The area of a trapezoid is the average of the bases times the altitude
A = (1/2) (b1+b2)h
We know that
b1+b2+h = 36
so,
b1+b2=36-h
Now Substitute
A = (1/2)(36-h)h
A = 18h-h2/2
Take the derivative and set it equal to 0
dA/dh = 18-h = 0
h = 18
If h = 18, then b1+b2 = 18 and A = (1/2)(18)2 = 162 = maximum area