We start by looking at the function:
y = x^2
If we take the derivative of both sides, we get the derivative that looks like:
dy = 2x * dx
dy/dx = 2x
We want to find where dy/dx = 5/4 (our slope of the tangent line is m = 5/4)
5/4 = 2x
5/8 = x
Since we now know that when x = 5/8, dy/dx = 5/4, we can now plug in that x back into the original function to get y:
y = x^2
y = (5/8)^2
y = (25/64)
Therefore our point of interest on the graph where the curve has a slope of m = 5/4 is:
(5/8, 25/64)
