Michael D. answered  01/20/16
Tutor
                    
        4.9
        (115)
            Selecting me gives you the best advantage in today's schools!
Basically you are taking one solution of a known concentration and diluting it with 'water'
If we have the original concentration of the solution and the volume of it added we know that the number of constituents in the solution is equal to the concentration multipled by the volume.
We als know that this number divided by the final volume of the solution is equal to the new concentration of the constituents in the solution.
We state this as C1*V1= C2*V2
or C2 = C1 *(V1/V2)
V1 is 4 mL
V2 = V1 plus 2 mL plus 4 mL  the dye solution(V1) plus the acid plus the water
C2 = C1 *(4/10) = 4 x 10 ^(-5) M 
all concentration changing relationships have as basis the nuimber of particles... mass of the materials in the process does not change in the process.
 
     
             
 
                     
                     
                    
Angelica J.
01/21/16