What are the dimensions of the rectangle

Question

The area of a rectangle is 65 yd² , and the length of the rectangle is 3 yd less than double the width. 

Answer 1

W  = width of the rectangle in yards

L  = length of the rectangle in yards

 

l = 2w - 3   From the problem

 

w (2w - 3) = 65

2w^2 - 3w - 65 = 0

 

using the quadratic formula

 

{-(-3) ± √[(-3)^2 - 4(2)(-65)]}/2(2)

[3 ± √(9 + 520)]/4

(3 ± √529)/4

(3 ± 23)/4

26/4 = 6.5  (we reject -5 as an answer because lengths are not negative)

 

double check the work

l = 2(6.5) - 3 = 10

10 x 6.5 = 65