Carlos has $10 more than Jeremy. Jeremy has $5 more than Michele. Altogether they have $80. What part of 100 does Michele have?

Question

THANK YOU.

Answer 1

Let the amount of money Carlos has be x.

Let the amount of money Jeremy has be y.
Let the amount of money Michele has be z.

 

Carlos has $10 more than Jeremy. Therefore: x = y + 10
Jeremy has $5 more than Michele. Therefore: y = z + 5
Altogether Carlos, Jeremy, and Michele have $80. Therefore: x + y + z = 80

 

This is a system of equations with three equations and three unknowns:

 

x = y + 10 (1)
y = z + 5 (2)
x + y + z = 80 (3)

 

Substituting (2) into (1), we'll have x = y + 10 = z + 5 + 10

Therefore, x = z + 15 (4)

 

Substituting (4) and (2) into (3):

x + y + z = z + 15 + z + 5 + z = 80;

3z = 80 - 15 - 5 = 60;

z = 20.

 

So Michele has $20 of the $80. (You can of course continue and solve how much Carlos has and how much Jeremy has.)

 

20 is what part (fraction) of 100?

 

It is 20/100, which is 1/5.

Answer 2

M=amount Michelle has

M+5=amount Jeremy has

M+5+10=amount Carlos has

M+M+5+M+5+10=80

3M+20=80

3M=80-20

3M=60

M=60/3

M=$20 for Michelle

what part of 100 is 20 ?

20/100=2/10=1/5