Michelina M.
asked • 01/12/16
the perimeter of a rectangle is 198 and the length is 42 less than twice the width. find the dimensions of the rectangle
Carol H.
answered • 01/12/16
Masters' Degree in Mathematics with 35 Years of Teaching Experience
Let w = the width
Let 2w - 42 = the length
P = 2l + 2w
198 = 2(2w-42) + 2w
198 = 4w - 84 + 2w
282 = 6w
47 = w
l = 2(47) - 42
l = 94 - 42
l = 52
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