Inactive Tutor answered • 01/11/16
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New to Wyzant
LHS:
tan x/(sec x - 1)
= [tan x (sec x + 1)]/(sec2 x - 1)
= (sec x + 1)/tan x
Jackson L.
asked • 01/11/16show that tanx/(secx-1) = (secx+1)/tanx
pre calculus
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