Edward C. answered 01/06/16
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Caltech Grad for math tutoring: Algebra through Calculus
A vector equation of the line that passes through the point X0 = (1/2,0,-3) and is parallel to the vector V = 2i - 4j + k is given by X = X0 + tV. Writing X = (x,y,z) gives the parametric equation
(x,y,z) = (1/2,0,-3) + t(2,-4,1) = (1/2+2t,-4t,-3+t)
or the 3 parametric equations x = 1/2 + 2t, y = -4t, z = -3 + t
To find another point on the line pick any non-zero value for t. For example
t = 1 ==> (5/2,-4,-2) is a point on the line