Mark M. answered 01/03/16
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
By the Product Rule, (fg)'(x) = f'(x)g(x)+g'(x)f(x)
So, (fg)'(3) = f'(3)g(3)+g'(3)f(3)
= (-7)(-1)+(4)(5) = 27