Chloe W.
asked 12/30/15Explain how a polynomial can have roots that are not complex conjugates
2 Answers By Expert Tutors
Saleel M. answered 12/31/15
Fun and Creative Math / English Tutor with Management Degree
Finally we reduce both sides of the equation in order to get a polynomial on one side and zero on the other: -(x4 - 2x3 - x2) = x2 - 2x + 1 -x4 + 2x3 + x2 = x2 - 2x +1 0 = x4 - 2x3 - 2x + 1 This looks very different from where we started but no established mathematical rules have been broken. When you graph the final polynomial in an equation as P(x) = x4 - 2x3 - 2x + 1 you can clearly see where it intercepts the x-axis in two locations, meaning there are two real roots, and neither of them is equal to 1. It is not so obvious what the roots are when imaginary numbers are involved, in fact I would suggest that no real information can ever be derived from any equation or expression involving an imaginary number.
Mark M.
12/31/15
Mark M.
12/31/15
Hilton T.
Finally we reduce both sides of the equation in order to get a polynomial on one side and zero on the other:
-(x4 - 2x3 - x2) = x2 - 2x + 1]
12/31/15
Mark M.
04/20/16
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Chloe W.
12/30/15