Inactive Tutor answered 12/15/15
Tutor
New to Wyzant
To solve this, you must first create the expression that represents the area of the two shapes.
The original rectangle has the side lengths of 2x+5 and 4x+2. Area is length x width.
Area= (2x + 5)(4x + 2) or 2x(4x +2) + 5(4x +2) -Use the distributive property
Area= 8x^2 + 4x + 20x + 10 - combine like terms
Area= 8x^2 + 24x + 10
You will need to do the same for the square.
The original rectangle has the side lengths of 2x+5 and 4x+2. Area is length x width.
Area= (2x + 5)(4x + 2) or 2x(4x +2) + 5(4x +2) -Use the distributive property
Area= 8x^2 + 4x + 20x + 10 - combine like terms
Area= 8x^2 + 24x + 10
You will need to do the same for the square.
The original square has the side lengths of x+1 and x+2. Area is length x width.
Area= (x+1)(x+2) or x(x+2) + 1(x+2) - use the distributive property
Area= x^2+ 2x + 1x + 2 - combine like terms
Area= x^2 + 3x + 2
Area= x^2+ 2x + 1x + 2 - combine like terms
Area= x^2 + 3x + 2
Now you must subtract the area of the square (which is unshaded) from the area of the whole rectangle.
Area= (8x^2 + 24x + 10) - (x^2 + 3x +2) - distribute the negative to all numbers in the second parenthesis.
Area= 8x^2 + 24x + 10 + (-x^2) + (-3x) + (-2)- now combine like terms
Area= 7x^2 + 21x +8
Area= 7x^2 + 21x +8
Use this final equation to find the area for the shaded area and complete the table.
For example, if x=3, plug 3 in for all x's within the equation and follow the order of operations (PEMDAS)
Area= 7(3)^2 + 21(3) +8
Area= 7(9) + 21(3) + 8
Area= 63 + 63 + 8
Area= 126 +8
Area= 7(9) + 21(3) + 8
Area= 63 + 63 + 8
Area= 126 +8
Area= 134