
Nickole H. answered 12/15/15
Tutor
4.8
(6)
Experienced Middle School Special Education Teacher
To solve this, you must first create the expression that represents the area of the two shapes.
The original rectangle has the side lengths of 2x+5 and 4x+2. Area is length x width.
Area= (2x + 5)(4x + 2) or 2x(4x +2) + 5(4x +2) -Use the distributive property
Area= 8x^2 + 4x + 20x + 10 - combine like terms
Area= 8x^2 + 24x + 10
You will need to do the same for the square.
The original rectangle has the side lengths of 2x+5 and 4x+2. Area is length x width.
Area= (2x + 5)(4x + 2) or 2x(4x +2) + 5(4x +2) -Use the distributive property
Area= 8x^2 + 4x + 20x + 10 - combine like terms
Area= 8x^2 + 24x + 10
You will need to do the same for the square.
The original square has the side lengths of x+1 and x+2. Area is length x width.
Area= (x+1)(x+2) or x(x+2) + 1(x+2) - use the distributive property
Area= x^2+ 2x + 1x + 2 - combine like terms
Area= x^2 + 3x + 2
Area= x^2+ 2x + 1x + 2 - combine like terms
Area= x^2 + 3x + 2
Now you must subtract the area of the square (which is unshaded) from the area of the whole rectangle.
Area= (8x^2 + 24x + 10) - (x^2 + 3x +2) - distribute the negative to all numbers in the second parenthesis.
Area= 8x^2 + 24x + 10 + (-x^2) + (-3x) + (-2)- now combine like terms
Area= 7x^2 + 21x +8
Area= 7x^2 + 21x +8
Use this final equation to find the area for the shaded area and complete the table.
For example, if x=3, plug 3 in for all x's within the equation and follow the order of operations (PEMDAS)
Area= 7(3)^2 + 21(3) +8
Area= 7(9) + 21(3) + 8
Area= 63 + 63 + 8
Area= 126 +8
Area= 7(9) + 21(3) + 8
Area= 63 + 63 + 8
Area= 126 +8
Area= 134