Mark M. answered • 12/14/15
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The outcome of one day does not affect the outcome of the next day. Your chances are always 1/1000.
Mark M.
That is what one would think. Yet according to the laws of probability each play is an independent event, i.e., it is no influenced by what happened before or what would happen after. Each day you start over. Each day you have only one chance in a thousand to win.
In another way. Each number has the same probability of coming up each day. On the first day 27 has one in one thousand chances of coming up. The next day 27 still has one in one thousand chances of coming up.
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12/14/15
Sean A.
ok thank you sir
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12/14/15
Mark M.
You are welcome!
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12/15/15
Matt G.
By the reasoning in the other response if you rolled a die 28 times you would only have a 1 in 6 chance to get a 6. On any single day, regardless of the result on another day it is a 1/1000 chance that is correct, but the chance to match in 28 tries would be: (total # of outcomes - total # not matched)/(total number of outcomes) (1000^28-999^28)/(1000^28) = 0.0276 (2.76% chance) Another way to figure it out is the chance you would lose them all. (999/1000)^28 = 0.9724(97.24%). 1 - this result gives you the same 0.0276. For the dice roll example in 28 tries it is a; (6^28-5^28)/(6^28) = 0.994 (99.4% chance that you roll a six)
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04/25/23
Matt G.
A simpler example, 4 independent dice roles(could do them on different days, doesn't matter). What is the probability that you will get a 6(or whatever number you pick) If you have 4 dice/rolls, the total number of possible results is 6x6x6x6 = 1296. The total results for the rolls that would not include six are 5x5x5x5 = 625. The probability if you roll 4 dice that you will get a six is (1296-625) / 1296 = 0.518. This can also be figured out by the same 1 - the chance to not get the number also 1-((5/6)^4) = 0.518 .
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04/25/23
Sean A.
12/14/15