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finding the phase shift

let y = √20sin(4piex+7e^-1)

what is the amplitude?

what is the period?

what is the phase shift?

10/30/2013 | Dalia from Pleasantville, IA

2 Answers by Expert Tutors

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Robert J. | Certified High School AP Calculus and Physics TeacherCertified High School AP Calculus and Ph...

4.6 4.6 (13 lesson ratings) (13)

Amp A = √20

Period T = 1/2 (solving 4piT = 2pi for T.)

Phase shift φ = -7/(4pi e) (solving 4piφ+7/e = 0 for φ.)

10/30/2013 | Robert J.

Andre W. | Friendly tutor for ALL math and physics coursesFriendly tutor for ALL math and physics ...

5.0 5.0 (3 lesson ratings) (3)

Let's compare your equation to that of a general sinusoidal oscillation:

y = A sin ((2*Pi/T) x - φ),

where A is the amplitude, T the period, and φ the phase shift. You have

y = √20 sin ((4*Pi) x + 7e^-1),

therefore the amplitude is A=√20, the period we get from

2*Pi/T = 4*Pi, which gives us T=1/2,

and the phase shift is φ=-7e^-1.

With this information you should be able to sketch the graph of the oscillation.

10/30/2013 | Andre W.

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