let y = √20sin(4piex+7e-1)
what is the amplitude?
what is the period?
what is the phase shift?
Amp A = √20
Period T = 1/2 (solving 4piT = 2pi for T.)
Phase shift φ = -7/(4pi e) (solving 4piφ+7/e = 0 for φ.)
finding the phase shift
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2 Answers
Let's compare your equation to that of a general sinusoidal oscillation:
y = A sin ((2*Pi/T) x - φ),
where A is the amplitude, T the period, and φ the phase shift. You have
y = √20 sin ((4*Pi) x + 7e-1),
therefore the amplitude is A=√20, the period we get from
2*Pi/T = 4*Pi, which gives us T=1/2,
and the phase shift is φ=-7e-1.
With this information you should be able to sketch the graph of the oscillation.