let y = √20sin(4piex+7e

^{-1})what is the amplitude?

what is the period?

what is the phase shift?

let y = √20sin(4piex+7e^{-1})

what is the amplitude?

what is the period?

what is the phase shift?

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Scottsdale, AZ

Amp A = √20

Period T = 1/2 (solving 4piT = 2pi for T.)

Phase shift φ = -7/(4pi e) (solving 4piφ+7/e = 0 for φ.)

New Wilmington, PA

Let's compare your equation to that of a general sinusoidal oscillation:

y = A sin ((2*Pi/T) x - φ),

where A is the amplitude, T the period, and φ the phase shift. You have

y = √20 sin ((4*Pi) x + 7e^{-1}),

therefore the amplitude is **A=√20**, the period we get from

2*Pi/T = 4*Pi, which gives us **T=1/2**,

and the phase shift is **φ=-7e**^{-1}.

With this information you should be able to sketch the graph of the oscillation.

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