Mark M. answered • 12/07/15

Retired math prof. Very extensive Precalculus tutoring experience.

^{2}-4i

^{2})(x+4)

^{2}+4)(x+4)

^{3}+4x

^{2}+4x+16)

^{3}+4x

^{2}+4x+16) = -3x

^{3}-12x

^{2}-12x-48

Navi M.

Also, how would I go about solving this problem if I have 4 roots?04/18/20

Mark M.

04/19/20

Where N.

How did the -4i^2 became +4? Did I missing something?07/20/20

Mark M.

07/20/20

Where N.

Thank you very much! Appreciate it07/22/20

Navi M.

Why does it become f(x) = a(x-2i)[x-(-2i)](x-(-4)]?04/18/20