square root of 3 sin(theta) +cos (theta) = 1

Question

The answer is between 0 < or equal to theta< 2pi

Answer 1

√3sinθ + cosθ = 1

 

Divide by 2 to get  (√3/2)sinθ + (1/2)cosθ = 1/2

 

                           cos(π/6)sinθ + sin(π/6)cosθ = 1/2

 

                                                sin(π/6+θ) = 1/2

 

So, π/6 + θ = π/6 or 5π/6

 

              θ = 0 or 2π/3