∞
∑ (n2-3n+5)/(n3+4n-1)
n=1
As n gets larger and larger, the n2 in the numerator dominates all other terms there, and the n3 in the denominator dominates all other terms there.
The series
∞
∑ (n2-3n+5)/(n3+4n-1) → ∑ n2/ n3 = ∑1/ n which is the familiar divergent p series with p =1.
n
∑ (n2-3n+5)/(n3+4n-1) → ∑ n2/ n3 = ∑1/ n which is the familiar divergent p series with p =1.
n
The series therefore diverges.