Mario T. answered 12/04/15
Tutor
4.5
(11)
Cornell University Class of 2015 BS in Mechanical Engineering
x(t) = ∫65tdt(from 0 to .5) + ∫65/2dt(from .5 to 1)
First part of equation:
∫65t from 0 to .5 --> (.5 being a half hour)
65t2/2 from 0 to .5 = 65(.5)2/2 - 0 = 8.125 miles
Second part of equation:
∫65/2 from .5 to 1 = 65t/2 = 65(1)/2 - 65(.5)/2 = 32.5 - 16.25 = 16.25 miles
total distance is equal to 8.125 + 16.25 miles = 24.375 miles