Inactive Tutor answered 12/02/15
Tutor
New to Wyzant
Hi Alexys,
f'(1) = limΔx→0 [f(1+Δx) - f(1)]/[(1+Δx) - 1]
= limΔx→0 [log2(1+Δx) - log2(1)]/Δx
= limΔx→0 log2(1+Δx)/Δx
= limΔx→0 log2(1+Δx)(1/Δx)
= log2e
= 1/ln2
= 1.4427