Youngkwon C. answered 11/30/15
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Hi Kristen,
With a half life time of 30s,
the equation for the remaining Radium-221 can be written as
R(t) = R0·(1/2)t/30 (Eq. 1)
where R0 is the initial amount and t is the elapsed time in seconds.
With 85% decayed, Eq. 1 is written as
0.15R0 = R0·(1/2)t/30
0.15 = (1/2)t/30
2t/30 = 1/0.15
(t/30) = log2(1/0.15)
t = 30·log2(1/0.15)
= 82.109
The answer is 82.109 sec.