Hyun C.

asked • 11/28/15

what would be the solutions to (sin2x+cos2x)^2=1?

I know that this can be expanded to (sin2x+cos2x) (sin2x+cos2x)=1, which can be multiplied to be sin^2(4x)+2sin(2x)cos(2x)+cos^2(4x)=1. Or am I missing something here? I'm not sure what to do after this. Please help! 

1 Expert Answer


Hyun C.

Ah! That makes much more sense now. Thank you!


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