Andrew M. answered 11/24/15
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
1) Let's pick variables for each type of candle:
t = tapers, v = votives, L = tea lights
The amount of money made from each type of candle sales will be
6t, 1.5v, .75L since tapers are $6, votives are $1.50, and tea lights are $.75
Maya: 6t + 1.5v + .75L = 431.25 eqn 1
Lorrin: 6t + .75L = 378.75 eqn 2
Sara: 1.5v + .75L = 251.25 eqn 3
We have 3 equations with 3 unknowns.
From equation 3: L = (251.25-1.5v)/.75
Substitute that value of L into equation 2:
6t + .75[(251.25-1.5v)/.75] = 378.75
6t + 251.25 - 1.5v = 378.75
6t - 1.5v = 127.5
t = (127.5+1.5v)/6
Substituting into equation 1:
6[(127.5+1.5v)/6] + 1.5v + .75[(251.25-1.5v)/.75] = 431.25
127.5 + 1.5v + 1.5v + 251.25 - 1.5v = 431.25
378.75 + 1.5v = 431.25
1.5v = 52.5
v = 35
t = (127.5 + 1.5(35))/6 = 30
L = (251.25-1.4(35))/.75 = 265
Each box contained 35 votive candles, 30 tapers, and 265 tea lights
********************************************************
2. Again, pick variables for each type of ingredient
f = pounds of fruit, n = pounds of nuts, c = pounds of carob chips
the money made from a 50 pound bag of mix is 50(6.7) = $335
eqn 1: f + n + c = 50 the bag contained 50 pounds of trail mix
eqn 2: n = c + 5 there were 5 more pounds of nuts than carob chips
Substitute c+5 in place of n inside equation 1:
f + c+5 + c = 50
f + 2c = 45
f = 45-2c
Given the cost of ingredients:
5.5f + 7.5n + 8.5c = 335
5.5(45-2c) + 7.5(c+5) + 8.5c = 335
247.5 - 11c + 7.5c + 37.5 + 8.5c = 335
5c + 285 = 335
5c = 50
c = 10
n = c+5 = 15
f = 45-2 = 25
The trail mix contained 25 founds of dried fruit, 15 pounds of nuts,
and 10 pounds of carob chips.
Hope this helps. Good luck with your work.
Andrew M.
11/24/15