Andrew M. answered 11/19/15
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
The chord goes from one edge of the circle to
the other, but not through the center. Draw a
line, 5 cm long, from the center of the circle to
the center of the chord, bisecting it into 2 pieces
of 12 cm each. Then draw a radius from the
center to one of the points where the chord
touches the edge of the circle. You now have
a right triangle with side lengths 5 cm, and
12 cm and a hypotenuse whose length is the
radius of the. circle.
Let's find the radius r.
From pythagoreans theorem a2+b2=c2
52+122=r2
r2 = 169
r = 13 cm
Since diameter is 2r the diameter of this
circle is d = 2(13) = 26cm
Jeff M.
Didn't read your response. Multiple ways and explanations for many problems. That's why I'm glad these sites exist.
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11/19/15
Andrew M.
11/19/15