You will need the binomial distribution B(5,0.68;k) with probabilities P=C(5,k)*0.68^{k}*0.32^{5k} , where C(5,k) is the binomial coefficient.
a) k=0, P=C(5,0)*0.68^{0}*0.32^{5}=0.32^{5}=0.00335.
If you have a statistics calculator like the TI84, use the function binomialpdf(5,0.68,0).
b) k=5, use binomialpdf(5,0.68,5), get P=C(5,5)*0.680^{5}*0.32^{0}=0.145
c) k=3, use binomialpdf(5,0.68,3), get P=0.322
d) k≥2, P(k≥2)=1P(k<2)=10.039=0.961
On the TI84, use 1binomialcdf(5,0.68,1). (This is the cumulative distribution, it adds up
all values 0..k.)
10/17/2013

Andre W.
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